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Use binarySearch instead of a hand-written linear search
Yay. Change-Id: Icf686eb2d675da959f19edc856b521e6288dcea3
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@ -411,15 +411,11 @@ public class Suggest {
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final int score = wordInfo.mScore;
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int pos = 0;
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// Check the last one's score and bail
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if (suggestions.size() >= prefMaxSuggestions
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&& suggestions.get(prefMaxSuggestions - 1).mScore >= score) return true;
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final int length = wordInfo.mCodePointCount;
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while (pos < suggestions.size()) {
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if (sSuggestedWordInfoComparator.compare(wordInfo, suggestions.get(pos)) < 0)
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break;
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pos++;
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}
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final int index =
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Collections.binarySearch(suggestions, wordInfo, sSuggestedWordInfoComparator);
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// binarySearch returns the index of an equal word info if found. If not found
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// it returns -insertionPoint - 1. We want the insertion point, so:
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pos = index >= 0 ? index : -index - 1;
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if (pos >= prefMaxSuggestions) {
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return true;
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}
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