futokb/tools/dicttool/tests/com/android/inputmethod/latin/makedict/BinaryDictInputOutputTest.java
Jean Chalard 72b1c93941 Reinstate the shortcut-only attribute
Also add the blacklist attribute

Bug: 7005742
Bug: 2704000
Change-Id: Icbe60bdf25bfb098d9e3f20870be30d6aef07c9d
2012-08-31 22:11:52 +09:00

60 lines
2.1 KiB
Java

/*
* Copyright (C) 2011 The Android Open Source Project
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
package com.android.inputmethod.latin.makedict;
import com.android.inputmethod.latin.makedict.FusionDictionary.DictionaryOptions;
import com.android.inputmethod.latin.makedict.FusionDictionary.Node;
import java.util.ArrayList;
import java.util.HashMap;
import junit.framework.TestCase;
/**
* Unit tests for BinaryDictInputOutput.
*/
public class BinaryDictInputOutputTest extends TestCase {
public void setUp() throws Exception {
super.setUp();
}
public void tearDown() throws Exception {
super.tearDown();
}
// Test the flattened array contains the expected number of nodes, and
// that it does not contain any duplicates.
public void testFlattenNodes() {
final FusionDictionary dict = new FusionDictionary(new Node(),
new DictionaryOptions(new HashMap<String, String>(),
false /* germanUmlautProcessing */, false /* frenchLigatureProcessing */));
dict.add("foo", 1, null, false /* isNotAWord */);
dict.add("fta", 1, null, false /* isNotAWord */);
dict.add("ftb", 1, null, false /* isNotAWord */);
dict.add("bar", 1, null, false /* isNotAWord */);
dict.add("fool", 1, null, false /* isNotAWord */);
final ArrayList<Node> result = BinaryDictInputOutput.flattenTree(dict.mRoot);
assertEquals(4, result.size());
while (!result.isEmpty()) {
final Node n = result.remove(0);
assertFalse("Flattened array contained the same node twice", result.contains(n));
}
}
}